C++ Syntax - BlitzCoder.net

-=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- (c) WidthPadding Industries 1987 0\|565\|0 -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=-
Socoder -> C/C++/C#/Other -> C++ Syntax
Sun, 06 Jan 2008, 17:21
dna	Hello. I need some help with this C++ syntax struct date { int month; int day; int year; }; struct date nextday (now) struct date now; { if (now.day ==month.days(now)) if (now.month == 12) { now.day = 1; now.month = 1; ++now.year; } else { now.day=1; ++now.month; } else ++now.day; return (now); } int month_days(now) struct date now; { static int days_per_month[] = {31,28,31,30,31,30,31,31,30,31,30,31}; if (now.month == 2 && leapyear(now.year)) return (29); else return (days_per_month(now.month -1)); } int leapyear(year) int year; { if (year %4 ==0 && year % 100 !=0) \|\| year % 400 ==0) return (1); else return (0); } main() { static struct date d1= {4,24,2006}; } --v It's giving me some problem and I may have missed something. Any help is appreciated. Thanks -=-=- DNA
Sun, 06 Jan 2008, 17:29
Cower	What is the problem and why are you using old-style C syntax if you say you're using C++? Post the compiler errors and try to write clear code, rather than the mess you've got going there.
Sun, 06 Jan 2008, 17:44
dna	Here is the code with the compilers errors. struct date { int month; int day; int year; }; struct date now; struct date nextday (now) //static struct date now; { if (now.day == month.days(now)) //syntax error if (now.month == 12) { now.day = 1; now.month = 1; // syntax error ++now.year; } else { now.day=1; ++now.month; } else ++now.day; return (now); } int month_days(now) struct date now; //cannot convert & syntax error { static int days_per_month[] = {31,28,31,30,31,30,31,31,30,31,30,31}; if (now.month == 2 && leapyear(now.year)) return (29); else return (days_per_month(now.month -1)); } int leapyear(year) // year was not int year; //syntax error { if (year %4 ==0 && year % 100 !=0) \|\| year % 400 ==0) return (1); else return (0); } main() { static struct date d1= {4,24,2006}; } --v -=-=- DNA
Sun, 06 Jan 2008, 17:47
Cower	Beat me to it. On the positive side, mine is readable. typedef struct s_date date_t; date_t nextday( date_t now ); int month_days( date_t now ); int leapyear( int year ); struct s_date { int month; int day; int year; }; date_t nextday( date_t now ) { if ( now.day == month_days(now) ) { if ( now.month == 12 ) { now.day = 1; now.month = 1; ++now.year; } else { now.day=1; ++now.month; } } else { ++now.day; } return (now); } int month_days( date_t now ) { const int days_per_month[12] = {31,28,31,30,31,30,31,31,30,31,30,31}; if ( now.month == 2 && leapyear(now.year) ) { return (29); } else { return days_per_month[now.month - 1]; } } int leapyear( int year ) { if ( ( year % 4 == 0 && year % 100 != 0 ) \|\| ( year % 400 == 0 ) ) { return 1; } else { return 0; } } int main( int argc, char ** argv ) { date_t d1 = {4, 24, 2006}; // I'm not sure why you made this static return 0; } --v
Mon, 07 Jan 2008, 16:57
dna	Although this works it by itself, it does not work in the tutorials i'm using. -=-=- DNA
Tue, 08 Jan 2008, 16:32
dna	Thanks Agent Smith. I am working from a book.
Thu, 10 Jan 2008, 17:37
dna	Because of the age of my book I may need to use something online to assist my training. The structure syntax may be out of date although I think that this was written for the Unix shell and the VI editor. -=-=- DNA